36y^2+7y=15

Solution for 36y^2+7y=15 equation:

36y^2+7y=15

We move all terms to the left:

36y^2+7y-(15)=0

a = 36; b = 7; c = -15;
Δ = b2-4ac
Δ = 72-4·36·(-15)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-47}{2*36}=\frac{-54}{72}
=-3/4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+47}{2*36}=\frac{40}{72}
=5/9
$